General Physics

Pressure

6 real objectives extracted from your Physics notes.

Meaning of Pressure

Pressure is defined as:

The force acting per unit area on a surface.

Pressure tells us how concentrated a force is over an area.


Formula for Pressure

P=FAP = \frac{F}{A}

Where:

  • P = pressure (pascals, Pa)
  • F = force (newtons, N)
  • A = area over which the force acts (square metres, m²)

Unit definition:

1 Pa=1 N m21\ \text{Pa} = 1\ \text{N m}^{2}

How Force Affects Pressure

  • Increasing force (area constant) → pressure increases.
  • Decreasing force (area constant) → pressure decreases.

Example: Pressing harder on the ground increases the pressure on the ground.


How Area Affects Pressure (Exam-Critical)

  • Smaller area (same force) → greater pressure.
  • Larger area (same force) → smaller pressure.

This explains many everyday applications.

[Insert diagram showing the same force acting on small vs large area]


Everyday Applications of Pressure

Sharp Objects

  • Knives, needles, pins have small contact areas.
  • For the same force, they produce high pressure, making cutting and piercing easier.

[Insert diagram showing knife edge vs blunt surface]


Wide Surfaces to Reduce Pressure

  • Snow shoes, camel feet, tractor tyres have large contact areas.
  • This reduces pressure and prevents sinking.

[Insert diagram showing camel feet or snow shoes]


High-Heeled Shoes

  • High heels have small area of contact.
  • They produce high pressure, which can damage floors or soft ground.

Worked Examples (Teaching Core)

Example 1: Calculating Pressure

A force of 100 N acts on an area of 0.5 m².

Calculate the pressure.

Solution

P=FA=1000.5=200 PaP = \frac{F}{A} = \frac{100}{0.5} = 200\ \text{Pa}

Example 2: Effect of Area Change

A force of 200 N acts on:

  • (a) area = 2 m²
  • (b) area = 0.5 m²

Solutions

Pa=2002=100 PaP_a = \frac{200}{2} = 100\ \text{Pa}
Pb=2000.5=400 PaP_b = \frac{200}{0.5} = 400\ \text{Pa}

Smaller area → higher pressure.


Example 3: Finding Force

A pressure of 300 Pa acts over an area of 0.2 m².

Calculate the force.

Rearranging:

F=P×A=300×0.2=60 NF = P \times A = 300 \times 0.2 = 60\ \text{N}

Visual Aid: Formula Triangle

[Insert formula triangle with P at the top, F and A at the base]


Key Examination Tips (High-Value)

  • Always convert area to .
  • Do not confuse pressure (Pa) with force (N).
  • State the formula before substituting values.
  • Use realistic units and values.

Common Examination Errors (Examiner Insight)

Students often:

  • use cm² instead of m² without converting,
  • say pressure increases with area (incorrect),
  • confuse mass with force,
  • omit units in final answers.

Remember: pressure depends on both force and area.


Questions

Question 1

Define pressure.


Question 2

A force of 50 N acts on an area of 0.25 m².

Calculate the pressure.


Question 3

Explain why a sharp knife cuts better than a blunt one.


Question 4

A camel can walk on sand without sinking deeply.

Explain this using pressure concepts.


Solutions

Solution 1

Pressure is the force acting per unit area.


Solution 2

P=500.25=200 PaP = \frac{50}{0.25} = 200\ \text{Pa}

Solution 3

A sharp knife has a smaller contact area, producing higher pressure for the same force.


Solution 4

The camel’s wide feet increase the contact area, reducing pressure on the sand and preventing sinking.


End-of-Objective

A learner who has mastered this objective can:

  • define pressure accurately,
  • relate pressure to force and area,
  • apply P=FAP = \frac{F}{A} correctly,
    • explain everyday pressure applications clearly.

Meaning of Atmospheric Pressure

Atmospheric pressure is defined as:

The pressure exerted by the weight of air in the Earth’s atmosphere on all objects on the Earth’s surface.

Air has mass, and due to gravity, it exerts a force. This force acting over an area produces pressure.


Key Characteristics of Atmospheric Pressure

  • Acts in all directions (upwards, downwards, and sideways).
  • Acts on solids, liquids, and gases.
  • Decreases with increase in altitude (height above sea level).
  • Normally not noticed because it acts equally in all directions.

Effects of Atmospheric Pressure


(a) Atmospheric Pressure on Liquids

Atmospheric pressure allows liquids to:

  • remain in containers,
  • rise into straws or syringes when pressure inside is reduced.

Example: Drinking through a straw

  • Air pressure inside the straw is reduced when air is sucked out.
  • Atmospheric pressure on the liquid surface pushes the liquid up the straw.

[Insert diagram showing liquid rising in a straw due to atmospheric pressure]


(b) Atmospheric Pressure and Containers

Atmospheric pressure can cause containers to:

  • collapse if air inside is removed.

Example: Collapsing can

  • When air inside a can is removed or cooled, internal pressure decreases.
  • External atmospheric pressure pushes the can inward.

[Insert diagram showing a collapsing can experiment]


(c) Atmospheric Pressure on the Human Body

  • Atmospheric pressure acts on the human body at all times.
  • The body does not collapse because internal body pressure balances external pressure.
  • Changes in pressure can affect the ears (e.g. during climbing or flying).

Example: Ear popping

  • Occurs due to pressure difference between the inside and outside of the ear.

(d) Atmospheric Pressure and Weather

Atmospheric pressure influences:

  • wind movement,
  • weather patterns,
  • formation of clouds and rain.

Air moves from regions of high pressure to low pressure, producing wind.


(e) Atmospheric Pressure at High Altitudes

At higher altitudes:

  • atmospheric pressure is lower,
  • less oxygen is available,
  • breathing becomes more difficult.

Examples

  • Mountain climbers,
  • Aircraft cabins (pressurised).

[Insert diagram showing pressure decreasing with altitude]


Why We Are Not Crushed by Atmospheric Pressure

Although atmospheric pressure is large:

  • it acts uniformly in all directions,
  • internal pressure inside the body balances it.

Hence, there is no net crushing force.


Summary of Effects (Exam-Ready)

SituationEffect of Atmospheric Pressure
Straw drinkingLiquid pushed up
Collapsing canContainer crushed
Ears poppingPressure imbalance
High altitudeReduced oxygen
WeatherWind formation

Common Examination Errors (Examiner Insight)

Students often:

  • say air has no weight (incorrect),
  • think atmospheric pressure acts only downward,
  • confuse atmospheric pressure with liquid pressure,
  • fail to explain effects clearly.

Always mention air exerts force due to its weight.


Exam-Style Questions (Original)

Question 1

What is meant by atmospheric pressure?


Question 2

Explain why liquid rises when drinking through a straw.


Question 3

Describe what happens when a sealed can is crushed and explain why.


Question 4

Explain why breathing becomes difficult at high altitudes.


Worked Solutions (Beyond Excellent)

Solution 1

Atmospheric pressure is the pressure exerted by the weight of air on objects on the Earth’s surface.


Solution 2

Sucking air from the straw reduces the pressure inside it, so atmospheric pressure on the liquid surface pushes the liquid up the straw.


Solution 3

When the air pressure inside the can decreases, the greater external atmospheric pressure crushes the can inward.


Solution 4

At high altitudes atmospheric pressure is lower, so less oxygen enters the lungs during breathing.


End-of-Objective

A learner who has mastered this objective can:

  • define atmospheric pressure correctly,
  • describe its effects using real-life examples,
  • explain pressure-related phenomena logically,
  • answer structured and explanatory exam questions confidently.

What Is a Mercury Barometer?

A mercury barometer is an instrument used to measure atmospheric pressure using a column of mercury supported by the pressure of the atmosphere.

It works on the principle that:

Atmospheric pressure can support a column of liquid.

Construction of a Simple Mercury Barometer

A simple mercury barometer consists of:

  • A long glass tube, sealed at one end
  • The tube is completely filled with mercury
  • A mercury reservoir (trough or container)
  • The open end of the tube is placed below the mercury surface in the reservoir

When the tube is inverted:

  • Some mercury flows out into the reservoir
  • A column of mercury remains in the tube

At the top of the mercury column is a vacuum, called a Torricellian vacuum.

[Insert labelled diagram of a simple mercury barometer]


How the Mercury Barometer Works

  • Atmospheric pressure acts on the surface of mercury in the reservoir
  • This pressure pushes mercury up the glass tube
  • The mercury rises until:
    • the pressure due to the mercury column balances atmospheric pressure

At sea level:

  • The height of the mercury column is about 760 mm

This height is a measure of atmospheric pressure.


Relationship Between Mercury Height and Atmospheric Pressure

  • High atmospheric pressure → mercury column rises
  • Low atmospheric pressure → mercury column falls

Thus:

The height of the mercury column is directly related to atmospheric pressure.

Use of the Mercury Barometer

The mercury barometer is used to:

  • measure atmospheric pressure,
  • study weather changes,
  • predict weather conditions.

Weather indication

  • Rising mercury → high pressure → fair weather
  • Falling mercury → low pressure → cloudy or rainy weather

Why Mercury Is Used

Mercury is suitable because:

  • it has very high density (short column needed),
  • it does not wet glass,
  • it produces a clear, visible column.

Units of Atmospheric Pressure (BGCSE Level)

Atmospheric pressure may be expressed as:

  • millimetres of mercury (mmHg)
  • pascals (Pa) (introduced later)

At sea level:

  • Atmospheric pressure ≈ 760 mmHg

Summary of Key Points (Exam-Ready)

FeatureDescription
InstrumentMercury barometer
Liquid usedMercury
PrincipleAtmospheric pressure supports liquid column
VacuumAt top of tube
Normal reading~760 mm at sea level
UseMeasuring atmospheric pressure

Common Examination Errors (Examiner Insight)

Students often:

  • say mercury is pulled up by suction (incorrect),
  • forget the presence of a vacuum at the top,
  • confuse mercury barometer with aneroid barometer,
  • fail to relate height change to pressure change.

Always state that atmospheric pressure pushes mercury up.


Questions

Question 1

What is a mercury barometer?


Question 2

Describe the construction of a simple mercury barometer.


Question 3

Explain how a mercury barometer measures atmospheric pressure.


Question 4

State what happens to the mercury column when atmospheric pressure decreases.


Solutions

Solution 1

A mercury barometer is an instrument used to measure atmospheric pressure using a column of mercury.


Solution 2

It consists of a long glass tube filled with mercury, inverted into a mercury reservoir, with a vacuum at the top of the tube.


Solution 3

Atmospheric pressure pushes mercury up the tube until the pressure due to the mercury column balances the atmospheric pressure.


Solution 4

The mercury column falls because the atmospheric pressure supporting it decreases.


End-of-Objective

A learner who has mastered this objective can:

  • describe the structure of a mercury barometer,
  • explain clearly how it works,
  • relate mercury height to atmospheric pressure,
  • apply the concept to weather and pressure changes.

Weather Charts and Isobars

A weather chart is a map that shows:

  • atmospheric pressure,
  • weather conditions over a wide area.

An isobar is defined as:

A line drawn on a weather chart joining points of equal atmospheric pressure.

Isobars are usually labelled in millibars (mb).

[Insert labelled weather chart showing isobars]


Units of Pressure Used on Weather Charts

  • Atmospheric pressure on weather charts is measured in millibars (mb).
  • Typical sea-level pressure is about 1013 mb.

Pressure values:

  • Above 1013 mb → high pressure
  • Below 1013 mb → low pressure

High-Pressure Systems (Anticyclones)

A high-pressure area is a region where atmospheric pressure is higher than surrounding areas.

Isobar pattern

  • Isobars form closed loops,
  • Pressure increases towards the centre,
  • Isobars are often widely spaced.

Weather conditions

  • Clear skies,
  • Dry and sunny weather,
  • Light winds.

[Insert diagram showing high-pressure isobar pattern]


Low-Pressure Systems (Depressions)

A low-pressure area is a region where atmospheric pressure is lower than surrounding areas.

Isobar pattern

  • Closed loops,
  • Pressure decreases towards the centre,
  • Isobars often closely spaced.

Weather conditions

  • Cloudy skies,
  • Rain or storms,
  • Strong winds.

[Insert diagram showing low-pressure isobar pattern]


Wind Direction from Isobars

Wind direction depends on pressure differences.

Key rules:

  • Wind blows from high pressure to low pressure.
  • The greater the pressure difference, the stronger the wind.
  • Winds do not move directly across isobars; they tend to flow along curved paths around pressure systems.

Simplified BGCSE rule

Wind blows from regions of high pressure to regions of low pressure.

[Insert diagram showing wind direction relative to isobars]


Wind Strength and Isobar Spacing (Exam-Critical)

  • Closely spaced isobarsstrong winds
  • Widely spaced isobarsweak or gentle winds

This is because:

  • Close isobars indicate a large pressure gradient,
  • Large pressure gradient produces stronger winds.

[Insert comparison diagram: close vs wide isobars]


Predicting Weather Using Isobars (Step-by-Step)

To predict weather from a chart:

  1. Identify pressure values (in mb).
  1. Locate high-pressure and low-pressure areas.
  1. Observe isobar spacing.
  1. Predict:
    • type of weather (clear or rainy),
    • wind strength (strong or weak),
    • general wind direction.

Summary Table (Exam-Ready)

FeatureInterpretation
High pressure (>1013 mb)Clear, dry, calm weather
Low pressure (<1013 mb)Cloudy, rainy, windy weather
Close isobarsStrong winds
Wide isobarsLight winds
Wind movementFrom high to low pressure

Common Examination Errors (Examiner Insight)

Students often:

  • confuse isobars with contour lines,
  • say wind blows from low to high pressure (incorrect),
  • ignore isobar spacing when describing wind strength,
  • forget pressure units (millibars).

Always mention isobar spacing and pressure values.


Questions

Question 1

What is an isobar?


Question 2

Explain how isobar spacing indicates wind strength.


Question 3

Describe the type of weather associated with a low-pressure system.


Question 4

A weather chart shows closely spaced isobars around a low-pressure centre.

Predict the weather conditions and explain your answer.


Solutions

Solution 1

An isobar is a line drawn on a weather chart joining points of equal atmospheric pressure.


Solution 2

Closely spaced isobars show a large pressure difference over a short distance, producing strong winds.


Solution 3

Low-pressure systems are associated with cloudy skies, rainfall, and strong winds.


Solution 4

The weather is likely to be windy and rainy because the closely spaced isobars indicate strong winds and the low-pressure centre causes rising air and cloud formation.


End-of-Objective

A learner who has mastered this objective can:

  • interpret isobar patterns confidently,
  • use pressure values in millibars correctly,
  • predict weather conditions accurately,
  • explain wind strength and direction clearly in exam answers.

Pressure in Fluids

Fluids (liquids and gases) exert pressure because:

  • they have mass, and
  • they are affected by gravity.

In liquids, pressure increases with depth because:

  • the deeper you go, the more liquid is above you,
  • the weight of this liquid exerts a force.

Factors Affecting Pressure Beneath a Fluid Surface

The pressure at a point beneath a liquid surface depends on:

  1. Depth of the liquid (h)
  1. Density of the liquid (ρ)
  1. Gravitational field strength (g)

It does not depend on:

  • the shape of the container,
  • the surface area of the liquid.

Formula for Pressure in a Liquid

P=ρghP = \rho g h

Where:

  • P = pressure (Pa)
  • ρ = density of the liquid (kg m³)
  • g = gravitational field strength (≈ 10 m s²)
  • h = depth below the liquid surface (m)

Interpretation of the Formula (Exam-Critical)

From P=ρghP = \rho g h:

  • Increasing depth (h) → pressure increases
  • Increasing density (ρ) → pressure increases
  • At the surface (h=0) → pressure due to liquid is zero

Visual Concept: Pressure Increasing with Depth

[Insert diagram showing liquid in a container with pressure increasing downward]


Worked Examples (Teaching Core)

Example 1: Effect of Depth

Calculate the pressure due to water at a depth of 5 m.

(Take density of water = 1000 kg m³, g=10m s2g = 10\,\text{m s}^{2}.)

Solution

P=ρgh=1000×10×5=50000 PaP = \rho g h = 1000 \times 10 \times 5 = 50\,000\ \text{Pa}

Example 2: Effect of Density

Two liquids have the same depth of 2 m:

  • Liquid A: density = 800 kg m³
  • Liquid B: density = 1000 kg m³

Calculate the pressure in each liquid.

Solutions

Liquid A:

P=800×10×2=16000 PaP = 800 \times 10 \times 2 = 16\,000\ \text{Pa}

Liquid B:

P=1000×10×2=20000 PaP = 1000 \times 10 \times 2 = 20\,000\ \text{Pa}

Conclusion:

Higher density → higher pressure at the same depth.


Example 3: Finding Depth

A pressure of 30 000 Pa is measured in water.

Find the depth.

h=Pρg=300001000×10=3 mh = \frac{P}{\rho g} = \frac{30\,000}{1000 \times 10} = 3\ \text{m}

Everyday Applications of Liquid Pressure

Dams and Water Tanks

  • Dams are thicker at the bottom.
  • Pressure is greater at larger depths.

[Insert diagram showing a dam thicker at the bottom]


Divers and Submarines

  • Pressure increases as divers go deeper.
  • Divers must ascend slowly to avoid injury.

Water Jets from Holes

  • Water flows faster from holes at the bottom of a container.
  • Lower holes are at greater depth → higher pressure.

[Insert diagram showing water jets from different depths]


Key Examination Tips (High-Value)

  • Use metres, not centimetres, for depth.
  • Use correct density values (e.g. water ≈ 1000 kg m⁻³).
  • Always include units.
  • Pressure calculated using ρgh is liquid pressure only, not atmospheric pressure (unless stated).

Common Examination Errors (Examiner Insight)

Students often:

  • forget to convert cm to m,
  • confuse density with mass,
  • use P=AF instead of ρgh,
  • say pressure depends on container shape.

Remember: depth and density are the key factors.


Questions

Question 1

State the formula used to calculate pressure beneath a liquid surface.


Question 2

Calculate the pressure at a depth of 4 m in oil of density 900 kg m³.

(Take g=10m s2g = 10\,\text{m s}^{2}.)


Question 3

Explain why pressure at the bottom of a swimming pool is greater than near the surface.


Question 4

Explain why dams are built thicker at the bottom than at the top.


Solutions

Solution 1

P=ρghP = \rho g h

Solution 2

P=900×10×4=36000 PaP = 900 \times 10 \times 4 = 36\,000\ \text{Pa}

Solution 3

Pressure increases with depth because more liquid above exerts greater weight and force.


Solution 4

The pressure of water increases with depth, so the bottom of the dam experiences greater pressure and must be stronger.


End-of-Objective

A learner who has mastered this objective can:

  • relate liquid pressure to depth and density,
  • apply P=ρgh correctly,
  • apply P=ρghP = \rho g h correctly,
  • solve numerical problems confidently,
  • explain real-life applications of fluid pressure clearly.
OBJECTIVE
Describe how a manometer is used to measure pressure

What Is a Manometer?

A manometer is an instrument used to measure pressure, especially:

  • gas pressure,
  • pressure difference between a gas and the atmosphere,
  • pressure difference between two gases.

It works by comparing pressures using a column of liquid.


Construction of a Simple Manometer

A simple manometer consists of:

  • a U-shaped glass tube,
  • partially filled with a liquid (commonly mercury or coloured water),
  • one end connected to a gas supply,
  • the other end open to the atmosphere (or connected to another gas).

[Insert labelled diagram of a U-tube manometer]


How a Manometer Works (Principle)

  • Pressure applied to one side of the manometer pushes the liquid down on that side.
  • The liquid rises on the other side.
  • The difference in height of the liquid columns represents the pressure difference.

Key idea:

Greater pressure difference → greater height difference.

Using a Manometer to Measure Pressure

Case 1: Gas Pressure Greater Than Atmospheric Pressure

  • Liquid level on the gas side goes down.
  • Liquid level on the open side goes up.
  • The vertical height difference h is measured.

[Insert diagram showing gas pressure greater than atmospheric pressure]


Case 2: Gas Pressure Less Than Atmospheric Pressure

  • Liquid level on the gas side goes up.
  • Liquid level on the open side goes down.

[Insert diagram showing gas pressure less than atmospheric pressure]


Quantitative Relationship (BGCSE Level)

The pressure difference measured by a manometer is given by:

P=ρghP = \rho g h

Where:

  • P = pressure difference (Pa)
  • ρ (rho) = density of the liquid (kg m³)
  • g = gravitational field strength (≈ 10 m s²)
  • h = vertical height difference between the liquid columns (m)

Worked Example (Simple)

A manometer contains water of density 1000 kg m⁻³.

The difference in liquid levels is 0.20 m.

Calculate the pressure difference.

Solution

P=ρgh=1000×10×0.20=2000 PaP = \rho g h = 1000 \times 10 \times 0.20 = 2000\ \text{Pa}

Uses of a Manometer

A manometer is used to:

  • measure gas pressure in laboratories,
  • check pressure in sealed containers,
  • measure pressure differences in ventilation systems,
  • demonstrate pressure concepts in physics experiments.

Summary Table (Exam-Ready)

FeatureDescription
InstrumentManometer
ShapeU-shaped tube
Liquid usedMercury or coloured water
MeasuresPressure or pressure difference
Key readingHeight difference of liquid columns

Common Examination Errors (Examiner Insight)

Students often:

  • measure height along the tube instead of vertical height,
  • forget to convert cm to m,
  • confuse manometer with a barometer,
  • ignore which side has higher pressure.

Always identify which pressure is greater before explaining.


Exam-Style Questions (Original)

Question 1

What is a manometer?


Question 2

Describe the construction of a simple manometer.


Question 3

Explain how a manometer can be used to measure gas pressure.


Question 4

A manometer shows a liquid height difference of 15 cm.

If the liquid has a density of 1000 kg m⁻³, calculate the pressure difference.

(Take g=10m s2g = 10\,\text{m s}^{-2}.)


Worked Solutions (Beyond Excellent)

Solution 1

A manometer is an instrument used to measure pressure or pressure difference using a column of liquid.


Solution 2

It consists of a U-shaped tube partially filled with liquid, with one end connected to a gas source and the other open to the atmosphere.


Solution 3

Gas pressure pushes the liquid down on one side, causing it to rise on the other side. The height difference of the liquid columns indicates the pressure difference.


Solution 4

h=15 cm=0.15 mh = 15\ \text{cm} = 0.15\ \text{m}
P=1000×10×0.15=1500 PaP = 1000 \times 10 \times 0.15 = 1500\ \text{Pa}

End-of-Objective

A learner who has mastered this objective can:

  • describe the structure and function of a manometer,
  • use it to compare pressures accurately,
  • apply P=ρgh correctly,
  • apply P=ρghP = \rho g h correctly,
  • explain manometer readings confidently in exams.

What Is a Manometer?

A manometer is an instrument used to measure pressure, especially:

  • gas pressure,
  • pressure difference between a gas and the atmosphere,
  • pressure difference between two gases.

It works by comparing pressures using a column of liquid.


Construction of a Simple Manometer

A simple manometer consists of:

  • a U-shaped glass tube,
  • partially filled with a liquid (commonly mercury or coloured water),
  • one end connected to a gas supply,
  • the other end open to the atmosphere (or connected to another gas).

[Insert labelled diagram of a U-tube manometer]


How a Manometer Works (Principle)

  • Pressure applied to one side of the manometer pushes the liquid down on that side.
  • The liquid rises on the other side.
  • The difference in height of the liquid columns represents the pressure difference.

Key idea:

Greater pressure difference → greater height difference.

Using a Manometer to Measure Pressure

Case 1: Gas Pressure Greater Than Atmospheric Pressure

  • Liquid level on the gas side goes down.
  • Liquid level on the open side goes up.
  • The vertical height difference h is measured.

[Insert diagram showing gas pressure greater than atmospheric pressure]


Case 2: Gas Pressure Less Than Atmospheric Pressure

  • Liquid level on the gas side goes up.
  • Liquid level on the open side goes down.

[Insert diagram showing gas pressure less than atmospheric pressure]


Quantitative Relationship (BGCSE Level)

The pressure difference measured by a manometer is given by: